Java: How to check if a value is part of an enum?

[spark knoll]

I want to check if a input value coincide with an enum, I tried something, but I not believe what be the correct way:

import java.util.Scanner;

public class Ejercicio_1{

Scanner key=new Scanner(System.in);

public void Nombrar(){

    enum Nombres{
        Alejandra,Leonardo,Rosa,Guillermo,Gabriel,Daniel,Luisa,Ludmila
    }

   String[] nombre;
    nombre=new String[8];
    Boolean name=false;

    for(int n=0;n<nombre.length;n++){

        while(name.equals(false)){
            System.out.println("Ingresar un nombre:");
            nombre[n]=key.next();
            if(nombre[n].equals(Nombres.values())){
                name=true;
        }else{
                System.out.println("Nombre invalido");
            }

        }
    }

}

[plush geyser]

<@&987246399047479336> please have a look, thanks.

[honest dawn]

I see you're a beginner. There's a simpler way to do this, but if you want you can use loop (other method is Set/Map or Enum#valueOf(String))
First think what you need to edit is

for should be in while

[honest dawn]

And edit this if
if(nombre[n].equals(Nombres.values()))

Nombres.values() return array with all values this enum

one value != array with all value

You should use Nombres.values()[n].toString()

[n] to select 1 value from array and check them all one by one using the for loop
toString() to convert Enum to String
Enum != String

[dawn current]

and also don't use Boolean, use boolean

and use while(name) instead of while(name.equals(false))

       String[] nombre;
        nombre=new String[8];

you can do it in one line String[] nombre = new String[8]

Follow conventions for names

so Nombrar should be lowercase

and Ejercicio_1 shouldn't have a _

also name is misleading, why a name would be a boolean, rename this variable to a better name

and I advise you to use english, it's easier for everyone, and you are currently doing all english so you are not even trying to use spanish for all

And to answer your question

there are two ways

• either you use Nombres.valueOf and catch the exception
• or you do a loop over Nombres.values()

@spark knoll

[spark knoll]

I sorry, I must to wait to not be tired and do the things rigth, but thanks for help.

[dawn current]

what?