I want to verify the input of a numerical variable in Java.
Basically I want diferenciate when the value is 0 in case of this don't get input, or because the user input wat 0.
For now don't send the code because Is so long por the post.
#Verify input of a numerical variable in Java
shadow hinge
umbral robinBOT
<@&987246746478460948> please have a look, thanks.
cyan gull
we cant help u without seeing ur code
hexed cape
You could either use null or Optionals
cyan gull
since its entirely unclear how ur logic for representing "no input" works
if u have full control over it and just picked 0 as sentinel value cause u thought its a good idea, the better approach would be to use OptionalInt
hexed cape
Since your a novice, I'd suggest using optionals
shadow hinge
This is a simplifyed expample.
double num;
String bool;
System.out.println("Do you want insert a number?");
bool=key.next();
if(bool=="Yes"){
num=0;
} System.out.println(num);
I want know when 0 is a input or is the default value by not haben given a value.
cyan gull
yeah so use OptionalInt
hexed cape
Also pls don't call a String bool
And I'm assuming you want to use .equals instead of ==
shadow hinge
And I'm assuming you want to use .equals instead of ==
Yes, I do it this quickly, that's what I writed so.
hexed cape
kk