simple java question

[worthy kraken]

<@&987246399047479336> please have a look, thanks.

[hollow pilot]

Check your (, ) pairings...

And you should really use && there. There's no benefit to the lack of short-circuiting since the second term has no side-effects.

[real sinew]

ok

[real sinew]

where exactly am i looking

[hollow pilot]

every ( should have a matching ) (and vice versa)

You only have a few places to check. The if statement is the only complex one.

[real sinew]

i have it fixed in here

[hollow pilot]

Excellent that's the bracketing fixed. The 'incompatible types' is down to the fact that str.charAt(n) returns a char and "e" is a string. use 'e' instead (a char literal)

[real sinew]

in python "" and '' is the same

[hollow pilot]

• "e" is a literal String - use .equals(...) to compare strings.
• 'e' is a literal char - use == to compare chars.

A char is a primitive (a fixed-size type). a String is a reference type allowing Strings of varying lengths. Unlike Python ' is not used to represent strings.

[real sinew]

instead of doing == 'e'

can i do this?

because in the future i might have to compare string to string @hollow pilot

[hollow pilot]

The substring is more expensive (creating a new object).

And s.substring(beginIndex) is different from s.substring(beginIndex, endIndex).

[real sinew]

shouldnt this work now

[hollow pilot]

No because substring produces a String and 'e' is a char.

And note that the substring will be everything at and after position i + 3