open raptor
Hi need help in java code, Here is the Java Code.
class LogicalOperators {
public static void main (String [] args) {
int value1 = 1;
int value2 = 2;
if ((value1 == 5) && (value2 == 2));{
System.out.println("Correct");
}
if ((value1 == 1) || (value2 == 1));{
System.out.println("XX");
}
}
}
Kindly answer me in personal chat or here.
torn socketBOT
<@&987246399047479336> please have a look, thanks.
acoustic timber
you didnt ask anything yet
open raptor
There are eigth warrnings and i didn't understand that, Can you help me with that?
acoustic timber
share them
open raptor
so remove the simi colon?
acoustic timber
in the if, yea
open raptor
Now it shows 7 warrnings and another thing is that some of code is dim. just like in the screenshot
stray steppe
Read what the warnings say
open raptor
I didn't understand that but these are the warnings.
open raptor
I understand the English but how to fix that? I don't know.
the is the screenshot of my code.
stray steppe
Well, for example you defined value1 to be 1
Therefore, comparing it to 5 will always report false
open raptor
But I want to apply function and print the output
stray steppe
In that case, whatever is in "if" statement must be true
open raptor
Ok and what about the second if statnment
stray steppe
&& is a logical AND, if statement to the left is false then the entire expression is false and the right statement won't even be checked
open raptor
And can you Explain why must be true?
open raptor
&& is a logical AND, if statement to the left is false then the entire expressio...
Ok Thanks
stray steppe
In the second statement comparing value1 to 1 will always result in true, so the part after || won't run as well
stray steppe
And can you Explain why must be true?
Because that's how if statement work, do something if condition is true
open raptor
Because that's how if statement work, do something if condition is true
Ok If I want that condition is false and print something else Why it can't do that?
stray steppe
Then you need to add the else block
open raptor
In the second statement comparing value1 to 1 will always result in true, so the...
How to fix that too?
open raptor
Then you need to add the else block
?
stray steppe
else { code }
open raptor
else { code }
It didn't work
stray steppe
Because the if statement is always true
open raptor
but i wanted to add else statement too.
prime hedge
You have an else, but you can never enter it. Thus it's shown that way.
glass sphinx
@open raptor basically
your program is fine
but the values are constants
so the thing giving warnings can tell you that the ifs are pointless
if you got value1 and value2 from an external source - say user input - then it wouldn't complain
inner furnace
Or just pull it out to your own method.
public static void main(String[] args) {
doTheThing(1, 2);
}
public static void doTheThing(int value1, int value2) {
if (value1 == 5 && value2 = 2) {
System.out.println("Correct");
}
if (value1 == 1 || value2 == 1) {
System.out.println("XX");
}
}
The compiler will now know that the values could be different.
If doTheThing were private, a determined analyser could still conclude you never call it with values that would reach some code paths.