When checking, whether a number is in an array,

[cedar axle]

@scarlet narwhal has a question:

puvude

When checking, whether a number is in an array, what is the better way to write that, e.g. num == arr[i] or arr[i] == num?

<@&987246399047479336> please have a look, thanks.

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TJ-Bot

When checking, whether a number is in an array, what is the better way to write that, e.g. `num == arr[i]` or `arr[i] == num`?

Both ways are correct and will give you the same result. However, many developers prefer to write num == arr[i] because it follows a more natural reading order (reading left to right). This can make the code easier to read and understand for yourself and other developers who may be working on the same project.

Additionally, some developers argue that writing num == arr[i] can help prevent accidental assignment errors. If you accidentally write a single equals sign instead of a double equals sign, the compiler will throw an error because you cannot assign a value to a constant (e.g., 3 = num). On the other hand, if you accidentally write arr[i] = num, it will not throw an error and may lead to unintended consequences.

In summary, while both ways are valid in Java, writing num == arr[i] is generally preferred for readability and potentially preventing accidental assignment errors. Ultimately, consistency within your codebase is key, so choose one way of writing comparisons and stick with it throughout your project.

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TJ-Bot

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- AI generated response

[willow hedge]

Unless it's a boolean array, then any circumstance in which you intended to say a[i] == n, using a[i] = n instead would have resulted in a compilation error (in Java) - and if it were a boolean, then unless the n is an unassignable expression such as a method call or final value you wouldn't have received any protection from assignment (and if n were a literal true or false you should be saying just a[i] or !a[i] anyway).

So really, we'll just write it around whichever way reads most naturally for the circumstance.

[scarlet narwhal]

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