InputStreamer, how does it know when it is a newline

[uneven crag]

So I have this funciton: ```java
private static String readInput(InputStream f) throws java.io.IOException {
Reader stdin = new InputStreamReader(f);
StringBuilder buf = new StringBuilder();
char input[] = new char[1024];
int read = 0;
while ((read = stdin.read(input)) != -1) {

        buf.append(input, 0, read);          
    }                                              
    return buf.toString();                        
}```

After using functino I am analysing the string I get but I never ever match anything with "\n" why?

[sonic juniper]

<@&987246399047479336> please have a look, thanks.

[uneven crag]

I meant InputStreamReader btw

[plain dew]

why do you have such complicated code just to read a string ?

also wdym, why are you talking about newline ?

[uneven crag]

It is not actally my code, we got this from our prof if we wanna use it. Anyways the problem still remainer regardless tho.

[uneven crag]

What I mean is given a text file Hey how are you I am find you can see that there are two lines which are separated byt the whitespace \n. The string I get from this function contains it which I have verified using contains but now I just can't seem to use regex to pattern match it.

I have like ```java
Pattern pattern = Pattern.compile("0x[a-fA-F0-9]{6}|[A-Za-z]+|[0-9]+|%|\n|\.|"|\s*");
Matcher match = pattern.matcher(input);
if(match.group().equals("\n")){
tokens.add(new Token(TokenType.NEWLINE));
}

[sonic juniper]

Detected code, here are some useful tools:

[pure sentinel]

Why not just use Scanner. And why do you even care about \n if you are appending it to one String regardless

[plain dew]

List<String> lines = Files.readAllLines(Path.of("thefile.txt"));
Why can't you just do this ?

[plain dew]

nah

[pure sentinel]

How do u assume that he is reading a file. InputStream could be anything

[plain dew]

@pure sentinel

[pure sentinel]

Wp

[uneven crag]

I am making a parser for a language and I need to know whether there are comments or not so I can skip them guess what comments have in common, a new line so I felt that was a good idea. It might not be tho but rn that is what I am working with.

[pure sentinel]

Then yeah dont use a Scanner. Use FileNIO as Alathreon said or as alternative BufferedReader

[plain dew]

Ah, if you are making a parser, you first need to do a lexer in order to tokenize the data or just use a lib

[uneven crag]

if it was me I would use bufferreader but rn there is no point tho.

even if I used bufferreader I'd still need to pattern match "\n"

[plain dew]

why ? you are hjust making your life complciated for no reason

[pure sentinel]

No u dont

readLine();

[plain dew]

then what ? you read until you encounter this char or just use readLine or nextLine, what's the problem ?

[uneven crag]

Actually you are right.

[plain dew]

and please handle the files correctly

with a try with resources

[uneven crag]

wait a minute agian

I will try to use bufferreader which I think will be a lot easier honestly but rn the string I get is totally fine tho

[plain dew]

and just do this, it's what you need to do, you can't just use a regex, it won't work @uneven crag

[uneven crag]

Why can't I just pattern match \n?

[plain dew]

why would you ?

why are you trying to do something complex when you can do something simple ?

[uneven crag]

that is how I used to pattern match all my other key words and signs

[plain dew]

how do you know that they are not in a string ?

You can't match a language with a regex

you have to make a lexer

[uneven crag]

Yes it is inside my lexer. I am not really sure I understand what you mean. I read a file in my lexer class then I put my keywords/ Tokens I match using regex inside a list. Then I make a parse tree..

[plain dew]

ah right