How do I paralleize this piece of code in Rx java

[forest ridge]

Maybe<String> make(String url1, String url2) {
    return Maybe.fromCallable(() -> {
        String result1 = download(url1);
        String result2 = download(url2);
        return new State(result1, result2);
    }).subscribeOn(Schedulers.io())
}

[mossy fractal]

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Formatted code

Maybe<String> make(String url1, String url2) {
  return Maybe.fromCallable(() -> {
    String result1 = download(url1);
    String result2 = download(url2);
    return new State(result1, result2);
  }
  ).subscribeOn(Schedulers.io()) }

<@&987246623988019200> please have a look, thanks.

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result2 = download(url2);
return result1 + result2;
});
}

To parallelize this code in RxJava, you can use the `zip` operator to combine the results of two observables. Here's an example of how you can modify the code to parallelize the downloads:

```java
Maybe<String> make(String url1, String url2) {
    Maybe<String> download1 = Maybe.fromCallable(() -> download(url1))
            .subscribeOn(Schedulers.io());
    
    Maybe<String> download2 = Maybe.fromCallable(() -> download(url2))
            .subscribeOn(Schedulers.io());
    
    return Maybe.zip(download1, download2, (result1, result2) -> result1 + result2);
}

In this modified code, we create two observables download1 and download2 using the fromCallable operator. We then use the subscribeOn operator to specify that the downloads should be executed on a separate thread from the main thread.

Finally, we use the zip operator to combine the results of both downloads into a single string. The lambda function (result1, result2) -> result1 + result2 specifies how to combine the results.

By using subscribeOn(Schedulers.io()), each download will be executed in parallel on a separate thread. The zip operator will wait for both downloads to complete before combining their results.