urgent help needed im so lost. I have to swap the lowestint to the front and highest int to the back

[edgy pecan]

So ive got that working but how do im losing the other values in the original arrray. How can i stop this using basic java?

[fleet tusk]

<@&987246399047479336> please have a look, thanks.

Here is an AI assisted attempt to answer your question 🤖. Maybe it helps! In any case, a human is on the way 👍. To continue talking to the AI, you can use </chatgpt:1108714622413963314>.

To swap the lowest integer to the front and the highest integer to the back while preserving the other values in the original array, you can follow these steps:

1. Find the index of the lowest integer in the array.
2. Find the index of the highest integer in the array.
3. Swap the lowest integer with the element at index 0.
4. Swap the highest integer with the element at index (array length - 1).

Here's an example implementation in Python:

def swap_lowest_highest(arr):
    # Find index of lowest and highest integers
    min_index = arr.index(min(arr))
    max_index = arr.index(max(arr))

    # Swap lowest integer to front
    arr[0], arr[min_index] = arr[min_index], arr[0]

    # Adjust max_index if it was affected by previous swap
    if min_index == max_index:
        max_index = 0

    # Swap highest integer to back
    arr[-1], arr[max_index] = arr[max_index], arr[-1]

    return arr

# Example usage
original_array = [3, 7, 2, 9, 5]
result_array = swap_lowest_highest(original_array)
print(result_array)

Output:

[2, 7, 3, 5, 9]

This implementation swaps only the lowest and highest integers while preserving all other values in their original order.

[stark peak]

Please share code

[edgy pecan]

its all there but ill get a better pic

i cant find a way to delete smth from an array so im so confused

[glossy rampart]

hi. can you please paste the code instead of doing screenshots

[fleet tusk]

Please use this format for posting code:

```java
// Example java program
int value = 5;
System.out.println(value);
```

Which results in:

// Example java program
int value = 5;
System.out.println(value);

For syntax highlighting, you have to add the name of the language after the three backticks, like ```java. Please make sure to use exactly this format, so no space between the backticks and the language name, and a newline before the code starts. If done right, the syntax highlighting will even be applied to your text as you type, before sending.

firasrg5942 • used /tag id: code · Nov 24, 2023, 2:28 PM

[glossy rampart]

also

do not share everything you have on your source files

try to be precise on where you have issue

so we could help you fast

[edgy pecan]

sure

for (int i = 0; i ‹ array. length; i++ )
{
if (min > array[i])
{
min = array[i]; it
//System.out.printIn(min);
if ( max < array[1])
{
max - arrayli];
//System.out.printin(max);
array [e] - min;
array[array. length - 1] - max;
//System.out .printin(max); // 13
//System.out.printin(min); // 2
for (int ct - 0; ct < array. length; ct++)
{
System.out.print(array [ct] + " ");
}

so at the bottom

it prints the original array with my modified min at the start and max at the end

but it doesnt remove the min and max values from the original list

[glossy rampart]

can you write the array content like this : {1,2,3,4,..}

[edgy pecan]

the size of the array is declared by user input and all the values inside the array

so its random each test case

[glossy rampart]

alright. do you initialize min and max ?

[edgy pecan]

yeah just above the code i posted im sorry i didnt include it

[glossy rampart]

right

[ornate bridge]

i don't think that is the problem here
if i understand correctly Jo gets the correct values to min and max, but does not swap them with the values that were at the positions before.

[glossy rampart]

next, you need to look for minimum and maximum

[edgy pecan]

no i have the min and max working

[glossy rampart]

okay, next, you have to put min at 1st index and max at the end

 array[0] = min;
array[array.length - 1] = max;

[edgy pecan]

here you can see i print the min at the start and the max at the end but the original values remain in the list while i lose the others

[edgy pecan]

i have that done as well yes

[glossy rampart]

what is 'e' ?

[edgy pecan]

its zero in my code not sure why its 0 there

[ornate bridge]

then you need to not only record the min and max value, but also their index in the array.
and at the end set the values ate these positions to the values that were in the front/back

[edgy pecan]

this is how it looks on my code

[glossy rampart]

ah

[edgy pecan]

yes im asking how i would do this ive been trying so many ways

ive created a dummy array and tried to = it to eachother etc but i cant get it to work

im just lost haha

[glossy rampart]

seems the question wants your array sorted

just sort it

Arrays.sort()

[edgy pecan]

we cant we have to switch them for some god knows reason otherwise it wont pass the test case

[glossy rampart]

based on the "Expected answer" here, it looks it wants a sorted array

[ornate bridge]

you need to remember the index of the smallest element like this:

int min = array[0];
int minindex = 0;
for (int i = 0; i ‹ array. length; i++ ) {
  if (min > array[i]) {
    min = array[i];
    minindex = i;
   }
}

[edgy pecan]

yes but it wants you to swap them ive alrready tried to sort and got 0

[glossy rampart]

hmm

[ornate bridge]

please check the image that is in the post for more information

[ornate bridge]

after you got the index, you can swap the elements with the help of a temporary variable:

int tmp = a;
a = b;
b = tmp;

Then you just have to do that for min and max

[edgy pecan]

sorry do you mean to swap what with what?

the index of the min and the index of another part of the array?

[ornate bridge]

you have to replace a and b with accesses to the array for the min index and the index 0

if you do that, you swap the values

you copy the value from one position to tmp
then you copy the value from the other position to the first position
then you copy the value form tmp to the second position

[edgy pecan]

And that would remove the original min from the array?

Okay I’ll try that

[ornate bridge]

that would swap the two elements

for example

int[] array = {42,400,10};
int tmp = array[0];
array[0] = array[2];
array[2] = tmp;
// now array contains {10,400,42}

[edgy pecan]

Okay I will try this and get back to you!

Thank you for your help

[glossy rampart]

you can make that in a separate method for better readability

[edgy pecan]

Idc about readability the only thing that checks it is a robot

As long as it works!

[glossy rampart]

~~```java
static void swap(int[] array, int idx1, int idx2) {

int temp = array[idx1];

array[idx1] = array[idx2];

array[idx2] = temp;

}

👍

[edgy pecan]

so im getting one number now!

but missing one stil

apologie for the screenshot i cant copy paste it ill have to type it out

[ornate bridge]

yea, you have to do the same for the max too

since you also want to swap that one

oh wait

you just have a small bug in the last line of the picture

can you see the bug, @edgy pecan?

[edgy pecan]

oh

temp2

it works for every test case except this one

[ornate bridge]

then think about what numbers are swapped here and in what order.

[edgy pecan]

I’m lost haha

[ornate bridge]

what is the highest number? what index does it have?
what is the lowes number? what index does it have?
now do the swapping on paper to understand what went wrong here.

[glossy rampart]

public class MyTest {

    public static void main(String[] args) {

        int[] array = {10,2,4,5 };

        int minIndex = 0;
        int maxIndex = 0;

        for (int i = 1; i < array.length; i++) {
            if (array[i] < array[minIndex]) {
                minIndex = i;
            }

            if (array[i] > array[maxIndex]) {
                maxIndex = i;
            }
        }

        // Swap the minimum element with the first element
        int temp = array[0];
        array[0] = array[minIndex];
        array[minIndex] = temp;

        // Swap the maximum element with the last element
        temp = array[array.length - 1];
        array[array.length - 1] = array[maxIndex];
        array[maxIndex] = temp;

        // Print the modified array
        System.out.println("Modified array:");
        for (int i = 0; i < array.length; i++) {
            System.out.print(array[i] + " ");
        }
    }
}

try this out

[edgy pecan]

Because it’s index 0? The 10 I mean

[ornate bridge]

yep, exactly because of that

[edgy pecan]

Hmmm

Should I do a != theb?

An if statement

[ornate bridge]

if the max is at index 0 you have to do something differently, so an if might be good.

[edgy pecan]

I’m running off to a train now so I won’t be able to do much more on it but ty for ur help

[ornate bridge]

👍