Arrays and manipulation | Together Java | Page 1

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edgy coral <@&987246399047479336> please have a look, thanks.

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Here's an example of how you can replace duplicates with 0 in an array:

import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] numbers = {1, 2, 3, 4, 2, 5, 6, 3};

        for (int i = 0; i < numbers.length; i++) {
            for (int j = i + 1; j < numbers.length; j++) {
                if (numbers[i] == numbers[j]) {
                    numbers[j] = 0;
                }
            }
        }

        System.out.println(Arrays.toString(numbers));
    }
}

Output:

[1, 2, 3, 4, 0, 5, 6, 0]

In this example, we use nested loops to compare each element of the array with all the elements that come after it. If a duplicate is found (i.e., two elements have the same value), we replace the duplicate element with a zero.

Note that this solution modifies the original array. If you want to preserve the original array and create a new one with duplicates replaced by zeros, you can create a new array and copy the elements while replacing duplicates:

import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] numbers = {1, 2, 3, 4, 2, 5, 6, 3};
        int[] result = new int[numbers.length];

        for (int i = 0; i < numbers.length; i++) {
            result[i] = numbers[i];
            for (int j = i + 1; j < numbers.length; j++) {
                if (numbers[i] == numbers[j]) {
                    result[j] = 0;
                }
            }
        }

        System.out.println(Arrays.toString(result));
    }
}

Output:

[1, 2, 3, 4, 0, 5, 6, 0]

In this case, we create a new array called result and copy the elements from the original array numbers. Whenever a duplicate is found, we replace the corresponding element in result with zero.

#Arrays and manipulation