Setting path for file inside java project

[elder frost]

right now i have file inside my java project and filePath is set to/Users/myName/Desktop/directory/projectName-rest/src/main/resources/zip_code_market_tracker.csv. But when I deploy this it my path will break.

[broken hill]

<@&987246399047479336> please have a look, thanks.

[broken hill]

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[lament forge]

show the code please

[lament forge]

what is this lib ?

[old canyon]

Apache spark from the looks of it

Anyways, OP you can use the getResource method to grab the file in your resources folder

[elder frost]

get resource on the string path ?

[lament forge]

wait, is this really an example from their official docs ?
that's messed up 🤔
@old canyon

[old canyon]

Yeah but it's a dumb example lol

Out of all the paths they could have put

[lament forge]

I mean, I checked the doc and there seem to have no way to put an uri or inputstream, only a string

[old canyon]

Well nobody said spark was a good framework 😂

Even though we use it at government 😔

(not for prod tho)

[elder frost]

uh oh, should I look into something else ? im open to suggestions . @old canyon

opening a tsv/csv file with 7 million records

[lament forge]

jackson I guess ?

[umbral schooner]

I think you need to use open csv

Path path = Paths.get()

[lament forge]

Path.of

[umbral schooner]

Then read with CsvReader

[elder frost]

why is it not a good framework though aha its supper slow for me

[umbral schooner]

I mean he will need that get() to do ClassLoader.getSystemRousources()

That san example I know already

[lament forge]

Paths.get was replaced by Path.of

but you shouldn't do that at the first place

you should use Class.getResource or better, Class.getResourceAsStream

[umbral schooner]

Aha

Alright. Going to try that out

Thanks

[spring owl]

spark is more for the billions or trillions of records use cases