a[(a=b)[3]] | Together Java | Page 1

shy sphinx Dec 13, 2022, 10:37 AM

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Can someone explain in layman terms why this will print 1 ? They have posted an explanation but I can't seem to understand it

hardy sparrowBOT Dec 13, 2022, 10:37 AM

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<@&987246399047479336> please have a look, thanks.

hardy sparrowBOT Dec 13, 2022, 10:37 AM

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hardy sparrow <@&987246399047479336> please have a look, thanks.

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shy sphinx Dec 13, 2022, 10:43 AM

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I understand that array a is fully evaluated, so then a is assigned the value of B, but does that mean this assignment disappears completely and has no effect on the rest of the code ?

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Am I understanding it correctly that in essence it's this?: a[~~(a=b)~~[3]]?

quartz rampart Dec 13, 2022, 10:58 AM

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I'm kinda reading it as a[b[3]], but no clue if that's right

winter ravine Dec 13, 2022, 11:30 AM

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a = b will assign b to a, but also return b to the caller

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so it makes a = b and then uses that

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obviously u should never write such terrible code lol

shy sphinx Dec 13, 2022, 1:11 PM

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This is for the 1Z0-808 exam, they always use code like this to confuse us for the exam lol

shy sphinx Dec 13, 2022, 1:13 PM

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quartz rampart I'm kinda reading it as `a[b[3]]`, but no clue if that's right

This is what I was also thinking, but apparently the answer is a[3] which is 1, so I assume (a=b) is just assigned and then basically removed from there. This is the only thing that makes sense to me lol

quartz rampart Dec 13, 2022, 1:16 PM

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shy sphinx This is what I was also thinking, but apparently the answer is a[3] which is 1, ...

How do you get to a[3] = 1? a[b[3]], b[3] = 0 -> a[0] = 1

shy sphinx Dec 13, 2022, 1:21 PM

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Never mind I think I just got it

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( a [ (a=b)[3]] )

So a is first stored which is: {1, 2, 3, 4)

It then assigns B to A which is {2, 3, 1, 0}
There it grabs index 3 which is 0

Then uses that as an index to search up from the already stored array in a

a[0] = 1

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@quartz rampart This is correct, right ?

quartz rampart Dec 13, 2022, 1:26 PM

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I believe so, yea. The re-assignment appears to be completely useless

shy sphinx Dec 13, 2022, 1:29 PM

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Indeed, these exam questions are so confusing it's unreal PePeHands

severe prawn Dec 13, 2022, 1:30 PM

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I believe it first accesses 'a' and the assigns b to a and takes the value of b[3] and then a[0]
and if you print the value of a[0] it will diplay 2 since a is actually b now

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so it does get assigned but is not relevant in that particular statement

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quartz rampart Dec 13, 2022, 1:34 PM

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In the exam they might have wanted to show off that an array stays the same even when assigned to something else while being accessed

severe prawn Dec 13, 2022, 1:36 PM

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possibly. I guess they just wanted to show how arrays are accessed when the same array is assigned to some other array at the same time

shy sphinx Dec 13, 2022, 1:37 PM

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Definitely gonna fail this exam lul

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Thanks for the help boys

#a[(a=b)[3]]