torn willow
I have done questions a, b and c (my solutions for b and c are here) and the answer to a is log_a(2^r).
I am stuck on question d.
I have tried finding the nth term and common difference for the second sequence so I could then also find Tn but I didn’t know how to.
I think I could do (log_a(6) - log_(2)) + (log_a(12) - log_a(4)) and so on? Not sure though
ruby cometBOT
sweet panther
What do you observe for 6, 12, 24, and 48 in the second sequence? Then you'll notice there's a common difference after you applied the laws of logarithm.
,tex And yes you can also do $(\log_a(6) - \log_a(2)) + (\log_a(12) - \log_a(4)) + ...$ as $\sum_{n=1}^N a_n + b_n = \sum_{n=1}^N a_n + \sum_{n=1}^N b_n$ for real sequence $a_n, b_n$
steady briarBOT
Terry the Tyranitar
torn willow
This is my idea for this one
I don’t understand how u got there
I remember the mark scheme showing something similar though
burnt perch
6 = 2.3 12 = 3.2^2 24 is 3.2^3
Log(6)= log2 + log3
Log(12)= log(2^2) + log3
And continue to n
Do u realize it
burnt perch
No problem
real viper
.solved
