#X-intercept solutions to a linear equation

19 messages · Page 1 of 1 (latest)

hexed nimbus
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I understand that when n = n', we get the X intercept. But I'm confused how this can happen at any value other than 0 since n'/[L] has to = 0 right? If I did 1-1, I would get 0 on one side of the equation, but 1/[L] on the other side. Am I making some algebraic mistake here? Thank you!

raven lanternBOT
hexed nimbus
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Also why is the slope -1/Kd instead of 1/Kd

safe parrot
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May I ask what is the context of the image?

Also, the slope is negative, because the line is going down as ñ is going to the right.

In a Cartesian plane, the slope of a line is given by m = (Y_A - Y_B) / (X_A - X_B);
If the function representing the line is increasing when X_A < X_B, then Y_A < Y_B;
If the function is decreasing when X_A < X_B => Y_A > Y_B; (Y changes sign)

This results into a negative sign in m = (Y_A - Y_B) / (X_A - X_B);

hexed nimbus
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I just dont understand how it's able to have any intercepts shown in the picture at all since the equation should only have one at 0,0 right

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Actually, it seems like I was confusing the x axis for n instead of ñ

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still, its difficult for me to interpret, can you give any explanation?

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how can ñ = n on one side, and not make ñ/[L] a number greater than 0

safe parrot
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I reevaluated your first question. I was mistook it for another thing.
Anyway, here is the idea: you want to know why when n=ñ, ñ/[L] gives a different result than n-ñ / K_d = 0;
well, n=ñ happenes ONLY when ñ/[L] = 0, in other words, the equality is available ONLY when ñ=0 (0/[L] = 0-0 /K_d)

It doesn't apply to any ñ value, because the x-intercept value is tied to the relation f(x) = 0; If one works, the other one will too; If one fails, the other one will follow;

hexed nimbus
safe parrot
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I understand your point. This is biology based which makes the problem even harder because of the notation; To explain you, I have to first understand for myself.
The best i cand do now is help you with an AI solution, but only if you want.
I realised what this all is, but I can't explain it further. Sorry

hexed nimbus
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thank you so much for your help regardless

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🙏

safe parrot
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As an idea, it all comes down to you extract data from the graph, and the smalles mistake in the algrebra can get to the wrong answer

safe parrot
hexed nimbus
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no it is ok, thank you again for responding

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.close