#Would someone be able to have a whole walk through of this worksheet with me please? (non calculate)

59 messages · Page 1 of 1 (latest)

quick timber
#

I'm just not really confident in matrices, circle graph and sin graphs etc and would appreciate if you can explain and teach me. Is okay if not. Thank u.

heady umbraBOT
quick timber
#

Hello

quick timber
#

🤔

#

T-T

quick timber
#

plz help

nimble light
#

hey, you still need help ?

random kite
#

I'm available

#

For a while

quick timber
#

hii

#

Yes please, I need help on question 3,7,10. Im on question 18 rn.

nimble light
#

What kind of help do you need with on 3,7,10 ? Having trouble to start or trouble at a given point?

quick timber
#

I dont really understand the question

nimble light
#

The three of em ?

quick timber
#

yeah

nimble light
#

Well for 3. you are given the equation of a line and 2 points of which the coordinates can be deduced from said line equation, then you have to calculate the length from A to B

#

In the 7. you have a graph of a function and are asked to give its expression

#

on 10 I assume you would need to find the x-intercept and y-intercept, plus vertex perhaps and sketch the curve as precisely as you can by hand

quick timber
#

what is intersection mean on Q10?

nimble light
#

I suppose by intersection they mean same as the intersections asked on the 7, i.e. the x and y interceptions

#

mb mb 3 not 7

#

same as on 3 not the 7

quick timber
#

so i need to put both the interceptions of x and y when they equal 0?

nimble light
#

yeah you need to include the points (0,f(0)) and (f^(-1)(0), 0) to have a more precise sketch

#

and I think the vertex at -b/2a too

quick timber
#

For Q3, I think from the question it says A is y=0 and B is when x=0 so I need to sub these values in the equation to find the coordinates?

nimble light
#

yup

quick timber
#

ok

quick timber
#

turning point?

nimble light
#

yeah in parabolas

quick timber
#

thank you

nimble light
#

np

quick timber
nimble light
#

piece wise means a function that is defined piece by piece, you can say: for all x in [x0,x1], f(x) = ... and for all x in [x2, x3], f(x) = ....

#

on the image you can for example split it into two domains and define it in two pieces by lines

quick timber
#

oh ok thank you

#

this make much more sense now

#

haha

nimble light
#

yeah such functions can actually be quite interesting too

quick timber
#

I'm not sure how to lay out the ans, I got for 2<_ x<_1, f(x)=2 and I don't know how to write the domain of x in the middle part in inequalities, like i don't know if it is (bigger than )or ( bigger than or equal )

#

bc up to 1 is still stationary, and the 2nd line begins after 1?

nimble light
#

well bigger than or bigger than or equal would fully depend on whether the point is included or isn't. Now in your case there is no empty circle on the curve to denote the point isn't part of the curve so I would assume it belongs to the curve

#

well on this graph, without explicit conventions given, I would assume you can give the point to either of them

#

though perhaps not both at once

quick timber
#

okay

nimble light
#

if by <_ you denoted less than or equal then you'd have to do a simple greater than 1 for the second piece to avoid conflict

quick timber
#

okay how about when x=4, the same?

nimble light
#

oh yes

quick timber
#

okay

#

and the range is just 2<-f(x)<-5 ?

nimble light
#

yeah

quick timber
#

okay

#

for Q10, i think i need to put it in the qua fomula?

#

without a cal

nimble light
#

a cal ?

#

oh calculation

quick timber
#

calculator

nimble light
#

yeah no calculator I think since they say "sketch" so yeah quad formula and get vertex, x and y intercepts