#Measure Proof help

33 messages · Page 1 of 1 (latest)

tight edgeBOT
outer juniper
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beautiful handwriting

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while i would agree mu(\emptyset) = 0 is pretty obvious, i guess you need to write a little more

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the rest of the proof makes no sense to me so i’m not even sure what to say about it

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do you have a definition of ‘measure’ you can send?

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because i think we should start over from there

lethal sleet
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aww thanku! and yes !! i have one from the textbook we use

outer juniper
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okay cool

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for the empty set property, maybe you could write something like $$f(\emptyset) = \sum_{i \in \bZ\cap \emptyset} 4i = \sum_{i \in \emptyset} 4i = 0$$

rough currentBOT
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slayla

lethal sleet
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ahh ok ok I see, I realized i didn’t explain that part properly. for the second part of the proof i genuinely had no idea how to prove it 😭

outer juniper
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😭

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it's okay

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so now we have $A_1, A_2, \ldots$ pairwise disjoint sets and we want to show property 2 in the definition. if $$f\left(\bigcup_{i=1}^\infty A_i\right) = \infty,$$ i agree that $$\sum_{i=1}^\infty f(A_i).$$

rough currentBOT
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slayla

outer juniper
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but we should probably explain that

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and i also want to note that "the infinite union of A_i = \infty" isn't a good way to write that first equality

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if you want to write it in as plain english as possible, i would maybe write "the measure of the infinite union of the A_i's is infinity"

lethal sleet
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ahhh ok ok

outer juniper
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hmm i'm questioning if there is a typo in the problem now actually

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f({-1}) = -4?

lethal sleet
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me too…. actually i was lost at first because im sure this isn’t a measure

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if it’s 4i

outer juniper
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Z seems like a typo

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or it should be |4i|, or something

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i think if it said |4i| instead of 4i, or positive or nonnegative integers instead of Z, that would make f a measure

lethal sleet
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right right

outer juniper
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yea idk, i can carry forward with one of those corrections and continue explaining if you want lol

outer juniper
lethal sleet
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i emailed my professor so hopefully that clears it up but thank u!

outer juniper
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and then we have \sum f(A_i) >= 4 + 4 + 4 + ... = infinity

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that might need a little more explanation