#basic integration

29 messages · Page 1 of 1 (latest)

mint shuttle
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i didn't understand the proof or integration of (cot, sec ,csc) integrations

versed zodiacBOT
midnight temple
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What exactly don’t you understand about the integrals in question?

mint shuttle
cobalt field
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well the integration is 'proved' if you know the derivatives of the trig functions (and a few other functions)

midnight temple
# mint shuttle the proof of it self i can solve but feel has small feeling of not understandin...

It depends what you mean by a proof.
A proof would be to check that the derivative of the anti-derivative you get is indeed cot(x), sec(x) or csc(x). This shouldn't be too hard.

The integration methods for those all use some form of trig identity with substitution. If you can point out which of those exactly you're having trouble with, then it may help. Otherwise it's hard to say what you're having issues with really.

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Like is it more that you don't understand the identities used, or that you don't get some trick that was applied, or that you don't get the substitution that was used, etc.

vale pecan
vale pecan
midnight temple
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Well the thing is that I wouldn't call integration techniques a "proof," just like I wouldn't call differentiation techniques a proof of derivatives.
It's unclear what they are calling a proof from the get-go.

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If anything a convincing proof that ln|sec(x) + tan(x)| + C is the indefinite integral of sec(x) is just differentiating ln|sec(x) + tan(x)| + C and seeing that you get sec(x).

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But they don't seem to be meaning that

vale pecan
midnight temple
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Again my point is that it's not clear what they are calling a proof. It's not common to say that the computation of an indefinite integral is a proof.

vale pecan
midnight temple
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I suspect that it's probably some trig identity / rewriting trick that is used in those computations that they're having trouble with.

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We'll see I guess catshrug

mint shuttle
# midnight temple Well the thing is that I wouldn't call integration techniques a "proof," just li...

yeah i meant the technique to slove it (ik it's already memorised normal one)
and yeah if we took a d/dx of ln|secx + tanx| it got secx fr
but if we took the integral as a normal if we don't know the ln|secx + tanx| function yet
i saw that we it's normal like multiplying the secx with (secx + tanx / secx + tanx) which's one that's normal but heck yeah the first idea got is secx + tanx function like and if they r another methods to make it click?

midnight temple
mint shuttle
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and for ∫cscx dx
we use the same way but with (cscx - cotx/cscx - cotx)
but the same idea doesn't click
but the proof that if i diff the function ik it
to check my answer

mint shuttle
midnight temple
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However, note that it's not super common for those types of problems to be found in exercises in calculus textbooks. In general they're left as examples specifically because at this point students haven't necessarily been acquainted with those kinds of tricks and it's hard to come up with them if you've not seen it work in the past.

mint shuttle
midnight temple
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Yeah I think it's best not to overthink it. There isn't really an nice explanation to it other than it helps.

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And if you prefer other methods there's the one I mentioned above which may feel slightly less "out-of-the-blue" than multiplying by (sec(x) + tan(x)) / (sec(x) + tan(x))

midnight temple
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You could for instance rewrite sec(x) as 1/cos(x) and multiply by cos(x) / cos(x) to get something nice.

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This