#Stuck on proving trig identities (again)

40 messages · Page 1 of 1 (latest)

hearty cosmos
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Problem is I can only manipulate the left side of the equation, and I've been stuck on it for a good hour. Any help is appreciated

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smoky coveBOT
dreamy crater
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This is also not an identity

hearty cosmos
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I guess it works for pi but that's the only one I think will prove the identity is valid

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Geez my teacher is cooking up not an identity questions today

ionic acorn
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Assume it to be cot 90

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Then prove

coarse linden
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use calculator

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oh

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im sorry

ionic acorn
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What

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@hearty cosmos

stone bay
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you can however, find the set of values of x for which the above equation is true

hearty cosmos
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Ah I see

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I'm in the Canadian cirriculum for Math 31 which is calculus and it's a non calculator course

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Fnwojrkfkfn

stone bay
# hearty cosmos Ah I see

If you can, take a picture of the text of the question itself, above part a... cause i'm sort of in disbelief that the question would ask you to prove a non-identity as an identity

hearty cosmos
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Oh I'm out of home right now sorry

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It's something along the lines of "prove the following trig identities for all permissible values of x only by manipulating the left side"

brave osprey
hearty cosmos
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Should be soon

hearty cosmos
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Prove the following equations are identities like what

stone bay
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,rotate

sonic badgerBOT
brave osprey
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also the others may fail at few values

somber vault
somber vault
# sonic badger

They're talking about permissible values, not every single value

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But they haven't provided the range of values for which these are to be proven...

hearty cosmos
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I'm scared that I didn't do that section right. I struggled a bit on the first 2 questions on that section

brave osprey
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all values of x in R are permissble

somber vault
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¯_(ツ)_/¯

coarse linden
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,ROTATE

sonic badgerBOT
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Couldn't find an attached image in the last 10 messages.