trigonometry

[west meadow]

U there

[tiny nacelle]

yeh hi

[west meadow]

Do u know Pythagorean theorem

[tiny nacelle]

a^2 and b^2 is c^2?

[lunar sparrow]

what have you tried?

[tiny nacelle]

nothing so far

I did 180-90 making 90 but I mean other than that nothing

[lunar sparrow]

do you know tan ?

[tiny nacelle]

not really

[lunar sparrow]

this ?

[west meadow]

Okay then try finding the base

[tiny nacelle]

oh yea

but how do I know which one is the opposite?

if there are angles in both corners

[west meadow]

Depends on the angle

Chose one

[lunar sparrow]

the side opposite to the angle

[tiny nacelle]

but what if there are two angles?

apart from the right angle

[lunar sparrow]

it will be different for each

[tiny nacelle]

wait sorry wdym

there can be two opposite angles or?

[west meadow]

Dm me

[tiny nacelle]

why?

[lunar sparrow]

side opposite to angle means the side directly facing an angle , an angle is formed by two sides so the third is the opposite

[tiny nacelle]

okay thanks

[lunar sparrow]

sorry i just barged over to you

[west meadow]

For clarification

[tiny nacelle]

it's fine dw

[tiny nacelle]

so idk how to work this out still

[west meadow]

Find the base

[tiny nacelle]

16.7/13.1?

1.274

[west meadow]

Tats not how u get the base

[tiny nacelle]

I'm not sure then tbh

[west meadow]

Use Pythagorean theorem

[tiny nacelle]

My calcs messed up so it gave me 467m

[west meadow]

Let me do it

10.36

Am currently dealing with multiple chats to ensure I respond to u dm with the problem

[lunar sparrow]

tbf you dont need the other side (you can but you can do it without)

[clear light]

exactly
you can use sine and cosine in different orientations

[lunar sparrow]

Hi, sorry but you should not give uot direct answers i have been shunnned before

[tranquil wharf]

Ohh my bad

[lunar sparrow]

Nw

[tranquil wharf]

This wont result in a warning or whatever, right?

[lunar sparrow]

No but it is discouraged

[long gyro]

Np.

[lunar sparrow]

I assume

[long gyro]

Do you know how to continue?

🙂

[restive hollow]

do yk sohcahtoa

sin = opposite of that angle / adjacent of that angle

cos = a/h

tan = o/a

and inverse of one of these functions is the angle originally (so if sin(θ) = x, then sin^-1(x) = θ

then use that to calculate your angles :)