#help
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find where the zeroes are
ye its 3 and -1
like 4 of them have the same zeroes
yuh
the next step is to see the multiplicty of the zeroes
english
actually, you should look at the leading coefficient first and degree
what is the degree and sign of the leading coefficient?
like -2^3
no ^3 that's only for the term (x-3)
-2^3 is -8
(multiplicity is simply the power to which a variable-containing term is raised i believe
-2 is the leading coefficient
degree is odd sign negative
but why is -2 being cubed
degree is not odd
look at all the exponents of the factors and add them up
ye its 3
actually, you don't even need to worry about multiplicity of roots
there are 2 factors one has exponent of 3 the other has exponent of 1
(x-3)^3 and (x+1)^1
implied ^1 btw
maybe you thought no exponent meant 0?
but it means it is raised to the first power
yea
so even degree, negative leading coefficient, with zeroes at x=3 and -1
ok so its -2^4?
there is only one graph which has all these features
its B or C
does C look like it has x=3 as a zero?
i guess not
both the zeroes are negative for C right?
yea
(dont consider the leading coefficient to be raised to the power of [degree], since technically they are both their own things that control their own stuff)
the leading coeffieicient is not being raised to the degree of the polynomial
if the -2 was inside the parathesis in like (-2x+4)^4
then the leading coefficient would be (-2)^4
but that's not the case here
so its B
a better way to describe it would be how many times the root is repeated
so how many of that factor can you divide out while still having a polynomial
yes
in this example, the (x-3) factor is repeated 3 times, so you can divide this polynomial by (x-3) 3 times
interrobang !?
ye but i dont gotta do that right
not for this specific problem
in this example, you didn't have to worry about multiplicity bc there the leading coeff, degree and zeroes were enough
but based on the format im guessing its a necessary skill for you
i just lost aura
here is an example of where you would need to use multiplicity
the first equation with -2(x-3)^3(x+1), which was in the original example, can you tell if that is the blue or red graph?
prolly red
no
i guessed
(x-3) is cubed, so at x=3 the multiplicty should be 3
which means if you zoom in at x=3, it'll look like a cubic
fuck is a cubic
it flattens out before continuing the current direction
by direction, i mean increasing or decreasing
technically, it's the sign of the slope
the red one, when it passes x=3, you see how it looks like a straight line?
yea
that means the multiplicyt is just 1, since lines have a degree of 1
so you'd expect (x-3) to be raised to power of 1
for the red graph
if at x=a, the graph passes through it like a line, the multiplicity is 1, so it's just (x-a)
if it passes like a parabola, then multiplicity is 2, so it'd be (x-a)^2
if it passes like a cubic, it'd have multiplicity 3, so it'd be (x-a)^3
usually, multiplicites will only be 1, 2, or 3. They won't give you a mult. of 4, because it''s very hard to tell the difference between a multiplicity of 4 vs a mult of 2
since both will appear to "bounce" off the x-axis
yo ur smart
unc