I need help with exercise 8
PLEASE DON'T GIVE ME ANSWERS
small hints how to start I have no idea how to solve it
Just very small hints on what I should do thank you
#Polynomial exercise
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wise needleBOT
final plume
<@&286206848099549185>
past trail
!15m for future reference
wise needleBOT
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past trail
There's an obvious power of X you could factor out.
final plume
There's an obvious power of X you could factor out.
X^n?
You mean to separate X^n from all of power of Xs
Then factoring it out
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Not all terms have X^n
They do if i separate it
From all of em
I don't understand your hints honestly
past trail
All those terms have some power of X in common
It's just not X^n
Then you'll be able to factor it out and you'll only need to consider roots of a smaller polynomial.
final plume
Then you'll be able to factor it out and you'll only need to consider roots of a...
I will try it and tell you
final plume
All those terms have some power of X in common
Is it X^n+1
I hope this is not dumb
past trail
It's not dumb.
However you don't want negative exponents.
If you had X^5 + X^4 + X^3 + X^2 and you wanted to discuss its roots, the first thing you would do for instance is to factor out the biggest power of X they all have in common. In particular, you would take X^2 ( X^3 + X^2 + X + 1)
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Ooooo alright
past trail
Then you know that you've taken out all the 0-roots and you can focus on the others
Just easier to work with
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Then you know that you've taken out all the 0-roots and you can focus on the oth...
OKAY ITS X^n-1
They all turned X with power 3,2,1
past trail
Yep
So now you're only interested in the root at X=2 of this degree 3 polynomial
To show a polynomial has a double root at some x=a, you can either go the calculus approach and show that f(a) and f'(a) are 0.
OR remember that the polynomial has a double root at x=a if (x-a)^2 is one of its factors.
I guess it depends on what you're comfortable with and what you've done in this course so far.
final plume
I guess it depends on what you're comfortable with and what you've done in this ...
Yes thank you so much
I have done it using euclidean division
That's what they asked us for
Thank you for the two informations I didn't know about them
I tried to make another post btw
But I couldn't
Idk why
@past trail
That's what i wanted to post again
NEVER MIND IT WORKED
Sorry for the ping