#Am I cooked

21 messages · Page 1 of 1 (latest)

fleet radish
teal vaultBOT
torn nova
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What do you want help with here exactly

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I can help you

past valve
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can be solved using similarity

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y/x=qc/pc ; y/z=qa/ra

torn nova
past valve
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we have to prove the equation that 1/y=1/x+1/z

past valve
torn nova
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Oh Q

torn nova
past valve
barren wadi
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First prove triangle pac similar to qbc
And triangle rac to qab
( See order of triangle accordingly )
Then by cpst in both the similarities write sides proportional and substitute sides
Pa,qb,rc as x,y,z then find bc and ab
And at last substitute ac=ab+bc
Substitute value of ab and bc found earlier in cost of similarities

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If you want photo of my solution I can provide

fleet radish
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Thk

gentle quail
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First prove that triangle PAC is similar to QBC.
By CPST you get x/y=AC/BC ------> 1
Then prove that triangle RCA is similar to QBA.
By CPST you get z/y = AC/AB -------> 2
Add 1 and 2 by taking reciprocal of both
That way you get y/x+y/z = AB/AC +BC/AC
y/x+y/z= AB+BC/AC
This gives y/x+y/z=AC/AC
y/x+y/z = 1
y(1/x+1/z)=1
So 1/x+1/z=1/y

raven karma
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class 10 CBSE

fleet radish