#domain

124 messages · Page 1 of 1 (latest)

tiny girderBOT
weak root
#

Chat am i doing this right😭

pale oxide
naive pivot
weak root
weak root
#

and my teacher likes to use number lines to help visually

#

but I do not udnerstand

acoustic anvil
#

if you're trying to find the domain of this function (I am assuming the expression on the LHS is the original function), I'd probably leave the function in its original form, and tackle the domain restriction caused by the x in the denominator first.

weak root
#

which I find pretty simple but my orginal equations for the one im struggling with is

acoustic anvil
#

oh, should have shown this first

weak root
#

omg mb😅

acoustic anvil
#

ok, turning it into the expression $\sqrt{\frac{3x+4}{x}}$ is not wrong and does not change the domain

fervent hawkBOT
#

Koyuki

acoustic anvil
#

so you're all good on that part

#

so you can probably work with this. though if you find the original expression easier to work with, we can proceed with that as well.
your pick.

weak root
#

No I feel like the expression would be easier to work with

acoustic anvil
#

which one

weak root
#

the second

acoustic anvil
#

the new one, or the original?

#

so the new one yeah?

weak root
#

new one

acoustic anvil
#

sure

weak root
#

yesyes

acoustic anvil
#

so consider the new one.
tackle the most obvious thing first - the fraction

#

what can't the denominator of a fraction be?

weak root
#

0

#

right..

#

wait

acoustic anvil
#

cool, and here the denominator is just x

#

so what's the first domain restriction we have?

weak root
#

x cantnot equal 0

acoustic anvil
#

cool, keep that in mind

#

now, for a square root to be defined, we need its argument to be non-negative (so $\geq 0$).
agreed?

fervent hawkBOT
#

Koyuki

weak root
#

Yes cannot be nonnegative

acoustic anvil
#

excellent

#

now, the sign of a fraction depends on the signs of the numerator and denominator.
if the two sides of the fraction have the same sign (+/+ or -/-) we get a positive result (or 0), and if they differ we get a negative result.
agreed?

weak root
#

yes

acoustic anvil
#

fantastic

#

now, we'll need to turn to a useful tool for determining the domains of rational functions - sign analysis

#

first, let's get the obvious out of the way.
when does the denominator change signs? (in other words, when is the denominator 0 for this case?)

weak root
#

When X isnt 0....?😓

acoustic anvil
#

so the denominator is 0 when x isn't 0?

#

careful - there's a reason I provided the second question to help you out

weak root
#

when X=0

acoustic anvil
#

cool!

#

so we know that the denominator is 0 when x = 0.
because the denominator is linear, we also know that when x > 0, the denominator is positive, and when x < 0, the denominator is negative.
agreed?

weak root
#

Yes

acoustic anvil
#

nice

#

so next: the numerator

#

when is the numerator = 0?

weak root
#

when...3x+4=0

#

so

#

like -4/3

acoustic anvil
#

fantastic!

#

and just like the denominator, the numerator is linear.
so we know that for x < -4/3, the numerator is negative, and for x > -4/3, the numerator is positive.
agreed?

weak root
#

yes

acoustic anvil
#

nice

#

now, can the numerator be 0?

weak root
#

-4/3?

#

oh wiat

acoustic anvil
#

I mean, is the numerator allowed to be 0?

weak root
#

yes..?

acoustic anvil
#

will it cause any problems if the numerator is 0?

acoustic anvil
#

so the numerator is allowed to be 0, keep that in mind as well

#

and here is why we asked and answered all those questions.

weak root
#

ohhh so x is all real numberes expect for when X is less than 0 or greater than -4/3

acoustic anvil
acoustic anvil
#

yes, that is exactly the right concept!

acoustic anvil
acoustic anvil
#

massive implications there

weak root
#

wait in which case would I use or

acoustic anvil
#

use or if the value should fulfill either inequality

#

but here, x must fulfill both inequalities for it to be excluded from the domain

weak root
acoustic anvil
#

that is fine with "or", yes

#

not your example

#

if you use your example, you'd find that what you are essentially saying is all real x, except all real x!

#

oh and by the way

acoustic anvil
#

the greater than part is correct

weak root
#

its X is less or greater than 0? I thought that implied to greater than or equal to -4/3

acoustic anvil
#

nonono. remember what my very first question was?

#

I asked you what value the denominator cannot be

#

you mentioned x = 0

weak root
#

Ohhh yeah

acoustic anvil
#

which is correct, by the way

#

but that means you must include x = 0 as part of the exclusion

weak root
#

so in that case would both have the equal sign ?

acoustic anvil
#

no

#

x = -4/3 is allowed, as you said

weak root
#

but i thought the numerator could be 0

acoustic anvil
#

yeah the numerator can be 0

#

but you are writing the intervals of exclusion

#

not the intervals of inclusion

weak root
#

oh yeahh, im slow

#

Yes

#

that makes sense now

acoustic anvil
#

if you wrote the domain as intervals of inclusion then yes, there would be an equal sign on the x < -4/3, but not on the x > 0

weak root
#

now I see

#

X is all real numbers, X is greater than or equal to 0 and X is less than -4/3

acoustic anvil
#

uh

weak root
#

switching the greater and less

acoustic anvil
#

you put the equal sign on the wrong inequality if you are notating intervals of inclusion

#

x cannot be 0, remember?

weak root
#

wait is it possible to see a visual in the Domain

acoustic anvil
#

wdym

weak root
acoustic anvil
#

ok, so you want to notate the domain like in that image

#

yes, it is possible. you can try it now if you wish

weak root
acoustic anvil
#

or*

#

also, your opening brace is missing

weak root
#

Okay ill make those adjustments

idle raft
#

hi, a reminder to mark your problem as solved if you're done!

#

(you can do that with .close or .solved.)