Moment about a couple

[sturdy mason]

It would be the diagonal

For torque about the intersection of diagonals by the 2 couples

The perpendicular distance would be the length of that point to the couple itself

[loud imp]

my guide answer says 12cm is the distance, i cant figure out how though

[sturdy mason]

Is the diagram u have drawn correct according to the question?

What's the question

Can u share it

[loud imp]

ABCD is a parallelogram AB = 6, BD = 8, AD = 10
if two forces of equal magnitude 25 form a couple, then the magnitude of its moment = .........

all in cm

[sturdy mason]

Ur guide must have the wrong answer bcz

See the sides of the triangle are 6 8 10

It's a right angle triangle

So perpendicular distance must be 8

And the moment must be 25 X 8

Which is 200

What's the final answer though?

[loud imp]

6/10 is the cosine of angle a but i still dont know what's that got to do with the answer, and where die 6+10 even come from

[sturdy mason]

It seems wrong

Conceptually

But if u still want to confirm the doubt

U must ask this in a physics server

There is a server similar to ours

It's called

Physics

But as far as I know this is wrong

[loud imp]

alright, thanks for help

[sturdy mason]

Wlc