#Can yall tell me whats wrong here
34 messages · Page 1 of 1 (latest)
I don't see whats wrong or right about it
I think the mistake is here, you had 5x + 2 = 4
And then it became 5x = 4 + 2 instead of 5x = 4 - 2
What do you mean
Wait lemme re check it
Also here, take it step-by-step
x + y = 1
y = 1 - x
5x=4-2
5x=2
You divide 5 and 2 to 5 so it cancels 5 and 2 becomes 2/5
X=2/5
If
X=2/5
And
Y=-0.2
If you substitute that to 3x+2y=4
The answer isnt 4=4
Isnt that what i did but shorter?
x + 1 ≠ 1 - x
easy ass algebra
x = 2/5
y = 1 - 2/5
5/5 - 2/5 = 3/5 => 0.6
u can't do that on ur own gang
Im new to this
are you good at linear algebra?
Then explain to me how I find the dim of im(T) and what the im(T) is
ok brochacho
Look, the mistake is here as well
You replaced y incorrectly
It supposed to be 3x + 2(1 - x) = 4
Yo thx ive solved it
,,x+y=1 \implies x-1=-y \text{ or } 1-x=y