#How do I do this without trig?
urban nexus
fleet irisBOT
vivid stag
i forgot the formula for ecentricity of hyperbola
woeful python
i forgot the formula for ecentricity of hyperbola
e = c/a
woeful python
this should get u enough information
vivid stag
a is the major radius, b is minor radius
what is c
the focal length?
c=sqrt(a^2+b^2) right
have you learned the dot product yet
you do need trig to do it
thats the only way to find angles
why are you trying to avoid trig? That's like asking to find the log_2(8) "log base 2 of 8" without using exponents. Or even asking to find 1+1 without addition. It's not possible - that's why trig was invented
hmm I got cosine of the angle = 1/3 which is not one of the angles on the unit circle
woeful python
the focal length?
focal length/2
vivid stag
i thougth c was the distance from the center (origin) to each of the foci
woeful python
i thougth c was the distance from the center (origin) to each of the foci
thats true in elipses
where x^2/a^2 + y^2/b^2 = 1
urban nexus
@vivid stag my teacher says all of these problems can be solved without trig
and hes gonna yell at me if i use it
vivid stag
so he teaches you trig - and now he tells you to not use it?
also, the angle is cos^-1(1/3)
which isn't even a "special" angle
urban nexus
he didnt teach trig yet btw
vivid stag
so b must be a*sqrt(2)
for ecentricuty to be sqrt(3)
then you find the equation for the asymptotes
use the dot product formula for finding the cosine of the angle
and if you replace b^2 with 2a^2 it simplified to 1/3 - regardless of what a is
and that is not a special angle
its around 70 degrees
woeful python
If he’s asking not to use trig
Isn’t it more probable that its 90
Just wondering
vivid stag
If it's 90 that means the asymptotic slope is 1
Which means a=b
Which means eccentricity will be sqrt 2
woeful python
Makes sense
I don’t wanna put in the effort to actually solve that lmao
But I’m curious
vivid stag
