#Abstract Algebra: Integral Domain
27 messages · Page 1 of 1 (latest)
I'm guessing you're thinking of only real numbers and themselves right?
Try using matricies and see if you can find two matrices that multiply to equal a zero matrix
There are actually infinitely many rings that aren’t integral domains. Consider any non-zero $n$ and the factor ring $\mathbb{Z}/n^2\mathbb{Z}$. Can you see which element is a zero divisor in such a ring?
Ellie <3
That's not quite right, 9 is a square but the integers mod 3 form a field, in particular an integral domain.
What you probably mean to do is consider rings of the form $\mathbb{Z} / n^2 \mathbb{Z}$, in which $n$ is a zero divisor.
redsquirrel
Whoops yes
You can also just pick any non-prime positive integer
Consider $\begin{bmatrix}
1 & 0 \ 0 & 0
\end{bmatrix}
\begin{bmatrix}
0 & 0 \ 0 & 1
\end{bmatrix}$
HChan
you could think of it that way, I guess
no not really
just clever position of the zeros
if a matrix is filled with mostly zeros chances are it is a zero divisor
Well, clearly this is a non zero element multiplied by another non zero element that still gets a zero element
well it's just an example of your idea right?
The real number system with multiplication can't do this clearly but that's not very general
well often times we are given a certain system and asked if these properties apply or not
objects as in...
not all matrices multiply with eachother to get zeros clearly
but we can figure out at least one does
Good to hear!!
All objects having a certain property can be characterized by that property itself. But if you want a feel for what something is, it’s good to think of examples
For integral domains, you can look at any field (b/c all fields are integral domains) for an example of an integral domain