#Quadratic functions đ
29 messages · Page 1 of 1 (latest)
#11 is reflected over the x axis because the coefficient of the x^2 term is negative
that's not true for #12
the domain is the set of values that you can plug into the function and get a valid output, and for these two functions it's easy to see that you can plug in any number and get a valid input so the domain is all reals
also, because its x^2 coefficient is negative, that means it's opening downward and so it doesn't have a minimum
for #11 you need to say that it has a maximum
the domain for all of our functions (as of right now unless a word problem) is xeR
well yea, but thats true for the equation
the question is asking which is NOT true
oh yeah
im confused on the reflections because they both seem to be reflecting along an âx=somethingâ line, but one has âgraph reflects in x axisâ as true, but one doesnât
does that make sense?
(inserted the wrong picture sorry) 12 is blue 11 is green
axis of symmetry is a completely different concept to reflections
axis of symmetry is a line which the graph can be reflected across without changing
for parabolas, that will always be the vertical line passing through the vertex
i do know that
x=whatever the x coordinate of the vertex
so what are reflection axis? we werenât taught that đ
compare the graphs to the standard x^2 graph. if they're opening in the same direction as that graph, which would be up, then it's not reflected over the x axis
you can see that the green graph, however, is opening in the opposite direction to the x^2 graph so it had to have been reflected over the x axis
you can imagine taking the x^2 graph and then modifying it until you reach the function in question
so blue (12) is NOT reflected in the x-axis, but green (11) is. if i were to look at something how can i tell if itâs reflected or not? what do you mean by comparing it to the x^2 graph?
normally i wouldnât care this much but iâm locking in to keep my math average what it is currently
transformations are relative to the base graph. in this case the base graph is y=x^2
you can tell if the graph is reflected over the x axis based on whether it's opening up or opening down. if its vertex is at the base of the parabola, it's opening up, and if the vertex is at the peak of the parabola, it's opening down
so all of the extra numbers in y = a(x-p)^2 + q are just moving around the base quadratic of y = x^2? so since green is opening down, itâs automatically reflected across the x-axis? if thatâs the case are all downward-opening parabolas reflected across the x-axis? we only just started this and our teacher hasnât covered reflections or transformations or base graphs or any of those terms lol. i know what you mean by them now but this info is very reluctant to adhere to my brain
yes, yes, and yes
that's all correct
okay. that makes a lot of sense. i really wish i knew about this server last year when i was getting cooked in linear equations⊠thanks đ„Č