#f(x) = 2.sin(3x-pi)+1

208 messages · Page 1 of 1 (latest)

sweet socket
#

Hello guys, i'm studying maths right now, and i'm having some question regarding how to graph this fuction

wheat hingeBOT
sweet socket
#

So i was studying with Bing, and the AI suggested me that fuction, so i tried to solve it, and i think that i did

#

but i don't know, i ask to the AI to graph it, and it sent me this

BCO.png
#

And then i used a page, and it show me this

image.png
trim kernel
#

First factor out the 3

#

In the inside of the sine

sweet socket
#

ok?

trim kernel
#

So u get 2sin(3(x-pi/3))+1

#

Then u find the period

#

Do yk what the period of this graph is

sweet socket
#

i used this to find the period:
3x-pi=0
x=pi/3

#

sorry that isn't the period

#

2pi/3 it's the period

trim kernel
#

That’s horizontal translation

#

The pi/3

trim kernel
#

Ok now where is the midline

sweet socket
#

and then i did period/4

trim kernel
#

Yeah correct

#

That helps with graphing

sweet socket
#

Yeah

#

So i did this

#

To graph the fuction

trim kernel
#

Wait so what’s the question?

sweet socket
#

but i don't know i got so confused

#

I'm having issues to graph the fuction lmao

#

I think that i already solve it

#

So i did this, let me take a picture

trim kernel
#

So u graphed it

#

Lmao

sweet socket
#

Sorry i really need to sleep lol, let me send you the picture

#

Ok so i did this to graph the stupid fuction

#

So pi/3 it's like 1.04

#

and thats x so i should start to graph it on there

trim kernel
#

I mean to break it down, steps to follow would be

  1. Factor the inside part
  2. Find the period
  3. Find the vertical and horizontal translation
  4. Find the midline and amplitude (it helps to draw dotted lines for the midline and the lowest and highest y values)
  5. Scale by pi/4 and start graphing
trim kernel
sweet socket
#

Yeah, the Ai told me the same, but i don't know i thought that was something more advanced

trim kernel
#

Since ur scaling by the period/4

#

So on ur graph pi/3 would be 2 tick marks from the origin

#

Since the scale is pi/6

trim kernel
sweet socket
#

Mm... so the origin is 0, so i should start graphing on 2 ticks from the origin?

sweet socket
trim kernel
#

Above the 1

#

On the y axis

sweet socket
#

oh i was finding the period

#

so 2pi/3/4

trim kernel
#

So that would be ur starting point

#

Then u can start graphing key points every pi/6

#

Which is rlly fast since u divided the period by 4

sweet socket
trim kernel
#

Vertical translation is just the +1 part

#

In the original equation

sweet socket
#

Ohh right y = 0 something like that

#

well...

trim kernel
#

Since the parent sine function is at y=0 the +1 raises everything to y=1

sweet socket
#

Would you like to do a call?

trim kernel
#

Hmmm can’t atm

#

Maybe in like 10 mins

sweet socket
#

So let me try to draw the fuction

#

and then show it to you

trim kernel
#

Yeah

#

That works too

#

Also one other thing that helps me is that once u get ur key point for the function (pi/3,1) in this case, u can just graph the rest of the function by following the pattern highest point middle point lowest point middle point etc

#

If the sine is negative, the pattern starts at lowest point from the key point

#

When plotting points to the right of the key point

#

It works since u scaled ur x axis by the period/4

sweet socket
#

Ok so this is what i got

merry path
#

Hello, what can I help you?

sweet socket
#

did my best

sweet socket
trim kernel
#

Wait can u tell me what ur x and y axis say

#

Some of those numbers look a bit off

sweet socket
trim kernel
#

No like when it’s -2sin(3x+pi) +1

sweet socket
#

oh...

trim kernel
#

But they r the same thing ig

#

Since sine is an odd function

#

So sin(-x)=-sinx

sweet socket
#

i don't know if that answers your question

merry path
#

hi @trim kernel
r u good at python and javascript?

sweet socket
trim kernel
#

Um the x axis should be scaled by pi/6

sweet socket
#

it's because when i tried to put in on pi/6

#

i got more confused so i said

trim kernel
#

Cuz the period is 2pi/3

sweet socket
#

well maybe if i calculate pi, maybe will be more easy to me

#

so i did that

trim kernel
#

No, no need for that

#

Just keep it in terms of pi

sweet socket
#

Hello @merry path

trim kernel
#

It doesn’t matter the actual value of the tic marks if u know where ur point goes

#

So have the x axis by pi/6

sweet socket
sweet socket
trim kernel
#

Like think about it like the pi is 1 in ur mind

#

So it’s like 1/6

sweet socket
#

Yeah

trim kernel
#

I don’t understand what u scaled it by tho

sweet socket
#

its like this

trim kernel
#

Also why does the y axis go 1, 4/5, 2

sweet socket
#

it's x1

trim kernel
#

Maybe I’m misreading that

sweet socket
#

yeah lol

trim kernel
sweet socket
#

x1 means pi/3

#

x2 means pi/2

#

x3 means 2pi/3
x4 means 5pi/6
x5 means pi

trim kernel
#

That’s pretty confusing imo, is this standard notation?

sweet socket
#

Uh...

trim kernel
#

Like is this something the teacher taught

sweet socket
#

I don't know honestly

sweet socket
#

i didn't specify what x1,...x5 means sorry lol

#

it's like doing a = pi/3

trim kernel
#

Oh um u would refrain from creating ur own notation

#

If u were u, I would js scale by pi/6 and ignore the actual values after scaling

#

Also I still don’t understand the y axis

#

😭

sweet socket
#

Could you try to graph it?

trim kernel
#

Everything else is fine except the scaling

#

Like ur points r all fine

sweet socket
#

so i could see how do you graph

#

i understand x axis

#

think that i do

trim kernel
#

No I mean ur y axis is fine except one thing I don’t understand

sweet socket
#

so let me try to re-graph it with pi/6

trim kernel
sweet socket
#

thats 1,5

trim kernel
#

OHHHHHH

#

sorry mb

#

That looks like 4/5 to me

sweet socket
#

bro, are you saying my 1 and 5 it's so ugly 😭

#

Well...

#

yeah looks like a 4

trim kernel
#

I’m sorry

#

😔

#

Anyways ur graph is all good besides x axis thing then

#

I think ur good to go

#

👍

sweet socket
#

Yeah i think so

#

But, my first question was

#

i thought that i always draw like this

#

starting in 0

#

but in this example 2.sin(3x-pi)+1

#

it doesn't start on 0

#

so i got really confused

trim kernel
#

Usually y=0 is ur midline

sweet socket
trim kernel
#

But now the +1 shifts everything up so y=1 is ur new midline

sweet socket
#

so it's like this?

trim kernel
#

I assume the vertical line is for the x coordinate of the new key point

sweet socket
#

the vertical line it's the new midline

trim kernel
#

The midline is horizontal

sweet socket
#

fuck

trim kernel
#

Like how the graph oscillates from mid high low mid etc

sweet socket
#

Sorry, english isn't my first language, i don't know the meaning of midline on my native language

trim kernel
#

The mid part is where the middle line is

sweet socket
#

that's the reason why i look dumb

trim kernel
#

Np

#

I’m guessing ur native language is Italian

sweet socket
#

Spanish

trim kernel
#

Oh

#

Nice

#

I’m learning Spanish at school lol

sweet socket
#

Anything that you need, don't hesitate to dm me

trim kernel
#

Thanks :)

sweet socket
#

So let me try to find the meaning of midline

#

oh ok midline y = 1

#

and midline = eje medio

trim kernel
#

I drew it on the graph

trim kernel
#

Correct

sweet socket
#

OHHHH

#

midline it's

#

it's x axis?

trim kernel
#

Yeah ig

#

Since ur adding 1, the x axis is being shifted up 1 in a way

sweet socket
#

ohh yeah, you been trying to explain me that for 20 minutes

#

perfect i understand it finally

trim kernel
#

Nice

sweet socket
#

Ok

sweet socket
#

pi/3

#

no wait

#

ok

#

perfect

#

perfect i think i get it, but i need to study all that i ignored since it's very important

#

Ok, thank you so much @trim kernel 😄

#

If you need help with spanish, dm me

trim kernel
#

vertical translation is +1 btw

#

but anyways, i think ur good to go

#

gl

sweet socket
#

yeah it's +1

#

thanks, bye 😄

trim kernel
#

feel free to ask me if u have any other questions