#bound of this sequence
67 messages · Page 1 of 1 (latest)
what’s your question?
bound of the sequence
yes i tried using the absolute value but it isnt the way we did it at school
we took the highest member
how did you do it at school?
yes
you mean the first term?
yes
i see
can you tell me a rule that can help me find the bound of sequences
yes i tried approaching like this
generally you have to work on a case by case basis but generally you look at a few things like the first few terms and the limit of the sequence
if it exists
determining if a sequence is monotonic is of course useful
in this case it’s not but the terms decrease in absolute value
so its the best if j check first if its monotonic
usually a good strategy
if it’s monotonically decreasing then it’s bounded above by the first term and bounded below by the limit of the sequence (if it exists) or else it isn’t bounded below
a similar statement can be formed for monotonically increasing
here you can and it’s useful because the absolute value is monotonically decreasing
so
here it’s actually
its based on what kind a sequence it is
$-1 \leq a_n \leq \frac{1}{2}$
knief
so its bounded from above and below
yea
at school we would find
the first term
and then by logic i found the second one
1 and ½
but its not a good aproach?
approach*
i’m not sure wdym
^
so a1 is 1
well -1
mhm
the sequence would circle around 0
since the terms decrease in absolute value those are your bounds
there wasnt anything below -1 and above ½
you can show this by considering the subsequences consisting of negative terms and of positive terms separately
so i thought those are the bounds
ah
okay
thank you for your help 🙏
have a nice rest of your day ☺️
you too