#Matrix
ashen sigilBOT
gentle cloud
yes. but be carefull, Matrices are distributive over addition, but not commutative under multiplication.
so..
BXA⁻¹B⁻¹ = A⁻¹ (I + A)
atomic wren
yes. but be carefull, Matrices are distributive over addition, but not commutati...
Can you give me an example what do you mean
Communiative under multiplication means like AB is not the Same as BA?
gentle cloud
when working with matrices,
𝐴𝐵≠𝐵𝐴 in general. Matrix multiplication is not commutative.
atomic wren
Also what if its B-1(ABC), would that make AC or B-1ABC
gentle cloud
sorry. my english is not good at all. But if you multiply constants it works.
but with matrices is all different
atomic wren
Whats your native language?
gentle cloud
Whats your native language?
spanish
atomic wren
you can do the test
try:
A=[0 1] B=[3 4]
[2 4] [1 ...
Yes I understand that
atomic wren
Also what if its B-1(ABC), would that make AC or B-1ABC
But Thats my main question
sly kraken
no, ur not
gentle cloud
no, ur not
?
sly kraken
BXA⁻¹B⁻¹ = A⁻¹ (I + A)
= A⁻¹ +I
gentle cloud
exactly
sly kraken
jsut second
gentle cloud
Also what if its B-1(ABC), would that make AC or B-1ABC
i dont understand that. B - 1ABC. 1 is constant?
atomic wren
No
gentle cloud
what is 1?
atomic wren
Walt I dont know how to Write it
gentle cloud
u mean I?
atomic wren
B⁻¹
gentle cloud
ohhh
Also what if its B-1(ABC), would that make AC or B-1ABC ...... yes. its apply because you are not changing the order
atomic wren
@sly kraken @gentle cloud My Main question is if I have B⁻¹(ABC) what would that make
Is it AC or ABC B⁻¹
sly kraken
no, my mistake
gentle cloud
no, my mistake
wut?
atomic wren
Okay
sly kraken
atomic wren
But how can I get X in that picture above?
gentle cloud
if you are trying to isolate x the result is X=(AB)⁻¹(I+A)(BA)
sly kraken
r u ok?
atomic wren
if you are trying to isolate x the result is X=(AB)⁻¹(I+A)(BA)
Can u Tell me how u did it?
@sly kraken Whats Ur Problem g, if you dont wanna help then leave the Chat
I dont Need Ur weird questions
sly kraken
ok. Tom is right
gentle cloud
sure. You must to be carefull when you try to multiply matrices. so
ABXA⁻¹B⁻¹ = I + A
multiply on the LEFT by (AB)⁻¹
(AB)⁻¹ABXA⁻¹B⁻¹=(AB)⁻¹(I+A)
sly kraken
no, tom is false.
gentle cloud
(AB)⁻¹AB = I
sly kraken
beacuse (BA)-1=A-1*B-1
gentle cloud
its the same
lmao
shut up
XA⁻¹B⁻¹=(AB)⁻¹(I+A)
now multply both sides on the right by BA
XA⁻¹B⁻¹(AB)=(AB)⁻¹(I+A)(AB)
the same thing
atomic wren
I see
gentle cloud
X=(AB)⁻¹(I+A)(AB)
my only advice to you is...
be carefull with the order
matrices are different
atomic wren
But why is AB * (AB) ⁻¹ = 1
gentle cloud
no 1
atomic wren
Its like I
gentle cloud
AB*(AB)-1 = I
atomic wren
Which is 1 in matrices no?
gentle cloud
yes
gentle cloud
i dont know how to explain in english.
atomic wren
Okay I did it this way, you can try to Tell me if this mathematical correct or no
1sec
gentle cloud
so.
with A you can find A⁻¹. this is an important feature of A.
A inverse
when you do A*A⁻¹ you will get as a result I
also
A⁻¹*A = I
atomic wren
Haha am sorry
gentle cloud
no worries
do you have a book?
try to read why I is usefull.
and the properties.
and you will be able to understand better the topic.
atomic wren
I did it this way
I gave my Solution to gpt and said make it in spanish haha
Would this be correct?
atomic wren
okay I will do it ur way then
atomic wren
U did Great