Geometry -> angels?

[hasty wave]

i need some help to get some angels, how do i get the angel from A to be?
its for a game wher i got the radar on a car and a turret on a nother one

[wispy haven]

Angles of both triangles?

nvm i get what you mean

[hasty wave]

the angel from A -> B, this radar gets an angel and range to B its c and A is my turret

[hasty wave]

yeah

[wispy haven]

for the upper triangle

[hasty wave]

yeah yeah

[wispy haven]

you can use tan(a) = 50/100

then apply tan^-1 to both sides

tan^-1(1/2) plug this into a calculator and you will get your answer

for the other triangle we however need more info

lengths or angles

[hasty wave]

well we know the angel from C to B and range C to B

but only know the range A to C / C to A

[wispy haven]

50m and 100m?

[hasty wave]

yeah

that we know

we know the angel to the target "C" and the range to the target "C" we alos know the range to the lanucher "A" but we do now know the angel from the lanchuer "A" the target "B"

[wispy haven]

it’s not possible due to insufficient info

we need to know the height of the triangle

in order to solve for angle a

[hasty wave]

so from C to B?

[wispy haven]

doesn’t work

we need the height

it’s a must

[hasty wave]

well we do get the target azimuth and Elevation

from the radar

and range

[wispy haven]

how much

[hasty wave]

well iits the same height so 0 diffrence

[still sigil]

Assuming you want $\angle BAC$ and further assuming $\angle BCA = 90^\circ$, that can be calculated by
[\angle BAC = \tan^{-1}\left(\frac{50}{100}\right) \approx 26.6^\circ\text{ (to 1 d.p.)}]

As for the second scenario, $\angle BAC$ cannot be determined unless you know more information

[still sigil]

If you have more information, like any other interior angles, or the lengths of the sides of the triangle, then it may be possible.

[wispy haven]

no lengths are not enough

we either need height or 2 angles

[still sigil]

cosine rule would work no?
[ a^2 = b^2 + c^2 - 2bc\cos\angle A ]
where $\angle A$ is the included angle between sides $b$ and $c$

[wispy haven]

this is an alternative way

if we only got the height , this would be easy to solve

[idle bobcat]

angel