How do i calculate and derivate with lg, log and ln?

[wary tendon]

This supposed to be very easy but even then i dont understand anything:

[timber warren]

I think lg(a) here prefer to $\log_{10}(a) \text{ and } \ln(a) \text{ prefer to } \log_{e}(a)$

[formal oyster]

Fionna The Unemployment

[timber warren]

Definition is $a^b=x \Rightarrow \log_a(x)=b$

[formal oyster]

Fionna The Unemployment

[wary tendon]

See heres the thing

I dont understand anything of what u just said xD

[timber warren]

[wary tendon]

I figured out that 10^lg cancels it out

[timber warren]

Aww

[wary tendon]

and the remainder value was the anwsers

same with ln^e

[timber warren]

$a^b=x \Rightarrow \log_a(x)=b \Rightarrow a^{\log_a{x}}=a^b=x$

[formal oyster]

Fionna The Unemployment

[timber warren]

So $a^{\log_a{x}}=x$

[formal oyster]

Fionna The Unemployment

[timber warren]

In your problem $10^{\lg(1000)}$ and since $\log_{10}{1000}=\lg(1000) \Rightarrow 10^{\lg{1000}}=10^{\log_{10}(1000)}$

[formal oyster]

Fionna The Unemployment

[wary tendon]

I understand this now

[timber warren]

And apply this

[wary tendon]

If the bases are the same the remainder power becomes the anwser

Thanks

[timber warren]

I got u, np

[wary tendon]

Do you have any tips on how to use derivitives with natural log and log base 10 lg?

[timber warren]

Hm no not really $\frac{d}{dx}\log_a{x}=\frac{1}{\ln(a)x}$

[formal oyster]

Fionna The Unemployment

[timber warren]

iirc

So just keep in mind ln(e)=1 ig

[wary tendon]

Alrrrr

so is lg(10) = 1 too?

[timber warren]

Yes yes

,w log_10(10)

[formal oyster]

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[wary tendon]

alright thanks! i think i understand it now

apreciate the help

ima close the form for now