#Sets

16 messages · Page 1 of 1 (latest)

errant wolf
#

If irrational numbers are broken down into algebraic and transcedental irrationals, then if algebraic irrationals are denumerable, is it true that the most general countable set that we can create is R - {transcedental irrationals} ?

scarlet creekBOT
silk prism
#

note that all transcendentals are irrational and that algebraic numbers are countable

#

but the question itself is meaningless

errant wolf
silk prism
#

there's no such thing as the most inclusive countable numerical set, you can always add just an element countably many times to get a countable set

thorny solstice
silk prism
#

recursive reals?

#

if construction here means algorithmical explicit one (with the real condition over the numerical set), then we need to take account of certain other definitions

errant wolf
errant wolf
thorny solstice
#

For example, e and pi

errant wolf
#

anyways thanks for clearing my q up

#

.solved