#Why when we integrate with indefinite integrals, it's important to put a constant at the end
20 messages · Page 1 of 1 (latest)
yes sure.
like uk the differential of $x^{2}+2$, or $x^{2}+3$, or something like $x^{2}+n \forall n \in R $
Dhairya
WILL BE THE SAME- 2x
it doesnt matter what the constant is
hence the integral of 2xdx over from $-\infty$ to $+\infty$ would be $x^{2}+c$
Dhairya
not just $x^{2}$
Dhairya
yeah I see, so the c is there to cater that there can be any constant, like c represent a specific "family" of number?
no idts
except belonging to the complex no.s ig
no other exception
c just belongs to R
close this by typing .close
.close