#Number theory question
20 messages · Page 1 of 1 (latest)
the onces i gave here as examples are kinda easy but still could you pls help me understand how to solve these sums without brute force
Number theory question
I thought of this like:
if a^b+b^c+c^a is even, that means either all 3 a,b,c are even or one out of them is even and other 2 are odd. Now
if all three are even then max sum is 2024+2022+2020=6066
in 2nd case max sum would be 2024+2023+2021=6068
so overall max achievable would be 6068
Is this considered brute force? I think this is an optimal way to think about it?
ok uhh
rewrite 2) in terms of a = b(modn)
which implies (a - b)/n is in the set of integers
try to tinker with that
4(a+4)+3=x
6(b+3)+3=x
You can work from there as well
Ohhh..... thanks a LOOOT.
I didnt even think about it. tysm man
how to mark this as solved?

Thank you tooo <<3333
As someone who is a native bengali speaker lemme try to help
Oh it's already solved please mark it as solved
.solved I think
.solved
Post marked as solved by @fiery scaffold.
Use .unsolved if this was a mistake.
ohh hi... nice to meet you