#Some questions on number of functions
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the first qn can be solved by considering $f(x)={x}^{k} and f(y)={y}^{k}$
Dhairya
which leads us onto $[{xy}]^{k}={x}^{k} + {y}^{k}$
Dhairya
nope its (x^k)(y^k)
same ik that
@whole glen need help with 2nd problem?
yes
np
u a jee guy right?
so first well simplify the expression to get 3f(c)+2f(a)+f(d)=f(b)