This problem is so hard. ://

[fervent trench]

Please help me with this

[hidden ridge]

Multiply the ratinal expression by $\frac{\sqrt[3]{x}-4}{\sqrt[3]{x}-4}$

[carmine carbon]

146

[hidden ridge]

It will rationalise the numerator

In general any expression in the form $a^2 + ab + b^2$ when multiplied with $a-b$ gives $a^3 - b^3$ which is what we need for this.

[carmine carbon]

146

[vagrant elbow]

i think it is better to multiply by
$\frac{\sqrt{x^3 } + 4}{\sqrt{x^3 } + 4}$

[carmine carbon]

un_decorateur

[languid hinge]

You will get this

This doesn't yield anything

[languid hinge]

Nvm it works

[vagrant elbow]

I have misread the problem statement

they said "if you rationalize the numerator"
i have understood "rationalize the denominator"

[languid hinge]

B should just be x^3 -16

[languid hinge]

And A the numerator of this

It can't be evaluated any further

Waitttt

[languid hinge]

Ye I misread too