long pasture
At first I was going to use angle A to find side a but technically I don’t think I can because angle A is equal to tan^-1(a/b) and they only want me to solve the problem using sides b and c. I found that angle B = sin^-1(b/c) but idk how to use that to find side a :p
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chilly trail
If it's a right triangle as the diagram suggests, then a^2 = c^2 - b^2
long pasture
Ohhhhhhhh I heard that pythag could be used w these problems too but I just kept thinking in sohcahtoa terms
Thank you very much
long pasture
If it's a right triangle as the diagram suggests, then a^2 = c^2 - b^2
Soooo that makes my final answer a= sqrt(c^2 - b^2) right?
chilly trail
Soooo that makes my final answer a= sqrt(c^2 - b^2) right?
yeah, its easy to overlook pythag on trig problems
long pasture
yeah, its easy to overlook pythag on trig problems
I see, tyty
cunning cipher
I see, tyty
!done
blazing ventureBOT
I see, tyty
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cunning cipher
.solved