3D Vector Projections

[cobalt crystal]

Yeah, idk how to get further
I managed to get the dot products and cross product magnitudes of a-b, b-c, and a-c, but have no clue where to go now

[cobalt crystal]

a.b = 1/5, a.c = 1/6, b.c = 1/2
|axb| = 2sqrt(6)/5, |axc| = sqrt(35)/6, |bxc| = sqrt(3)/2

and i know the planes formula is (bxc).x=0
(using x because x is cross product, kinda lazy to format anything else)

x being the position vector

but im stuck from here

[lament pendant]

Try finding an orthogonal basis for P

[cobalt crystal]

whats that

[lament pendant]

Find finding a basis of perpendicular vectors for P

[cobalt crystal]

!close

how to close

.close