#Integration way harder then what it looks like

35 messages · Page 1 of 1 (latest)

limpid sentinel
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I can’t solve it tried it with many ways. I have the answer but can’t find the solution anywhere or do it myself.

The answer is given in the spoiler so you can’t match it yourself.

silent prairieBOT
limpid sentinel
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Can* match it

light bluff
civic venture
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@limpid sentinel this is the way

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you will have to solve this equation

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by the way, which book are you using ?

coarse skiff
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You get cos⁶t. Then express cos(t)^3 in terms of cos(3t) and square it. So, you easily get
32cos⁶t=cos(6t)+6cos(4t)+15cos(2t)+10. Integrate it. Then express it back in cos(2t), sin(2t) which then is easy in terms of tan(t)=x/2. So, yes, this should be way shorter on paper.

ebon sage
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you can also do it by induction with $I_p = \int \frac{dx}{(4+x^2)^p}$

scenic phoenixBOT
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bloubbloub

ebon sage
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also you can't decompose it further with PFD

civic venture
civic venture
scenic phoenixBOT
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barann0056

civic venture
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my bad it is :
$In=\int{}^{}cos^{n}(x)dx=\frac{cos^{n-1}(x)sin(x)+(n-1)\cdot I_{n-2}}{n}$

scenic phoenixBOT
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barann0056

limpid sentinel
limpid sentinel
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Sir himself was unable to solve it in doubt class

He tried tan2x substitution and by part too but it was too lengthily and was going nowhere

civic venture
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i mean it is pretty hard if you did not worked a lot on computation

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so its okay if you don't succed this one

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good luck for your calculus class

coarse skiff
civic venture
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.close

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@limpid sentinel type .close

limpid sentinel
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.close

silent prairieBOT
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Solved

Post marked as solved by @limpid sentinel.

Use .unsolved if this was a mistake.

limpid sentinel
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Same thing I did

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Still thanks

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Still very lengthy took very long