#Is my teacher wrong??

30 messages ยท Page 1 of 1 (latest)

gaunt oracleBOT
azure linden
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By the way,

My answer was: (m-n)^2
Correct answer was: 2(m-n)

normal glacier
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Your teacher is wrong

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I bet they misinterpreted $\log_{4}\left(1.6\right)^{2}$ as $\log_{4}\left(1.6^{2}\right)$

remote foxBOT
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BlockLayer2000

normal glacier
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The value of $\log_{4}\left(1.6\right)$ is definitely $m-n$, so the value of $\left(\log_
{4}\left(1.6\right)\right)^{2}$ is $\left(m-n\right)^{2}$

remote foxBOT
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BlockLayer2000

azure linden
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I showed her exactly that but on a graphing calculator and she said that's because of how they format it on calculators, but when writing it you can omit the brackets from the log. I said you can't because it just creates ambiguity and she just vehemently denied it.

normal glacier
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What? Most people would assume $\log_{4}\left(1.6\right)^{2}=\left(\log
_{4}\left(1.6\right)\right)^{2}$

remote foxBOT
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BlockLayer2000

azure linden
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she 100% didn't confuse it, it was an actual test that goes towards our grade, not just a randomly handed out practice test. It was made and checked over by the whole math department which is insane to me how this got every teacher's approval.

azure linden
normal glacier
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Wolfram agrees with you

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Geogebra agrees with you

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I can't think of any other calculators

azure linden
# normal glacier v

well the thing is she said when the square is there, it's on the argument and that to square the whole log, it has to be written like this which makes no sense because when the square is there, is it implying the whole thing is squared? I said to move the 2 down it must be log((1.6)^2) or log(1.6^2) and she said no

normal glacier
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well clearly the top three most respected math calculators disagree

azure linden
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this is where im sort of seeking consultation because i swear shes just flat out wrong

normal glacier
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Yeah, if you try to input that expression on geogebra is literally auto-formats to what you're saying

normal glacier
azure linden
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Alright ill show her on monday when i see her next. Thank you ๐Ÿ™

azure linden
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๐Ÿ˜ญ

normal glacier
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Sorry about that

normal glacier
# azure linden yeah they ain't gonna listen

If the goal was for you to evaluate $\log_{4}\left(1.6^{2}\right)$, then they shouldn't have a problem moving the parens. And if their goal was also to make you interpret $\log_{4}\left(1.6\right)^{2}$ as $\log_{4}\left(1.6^{2}\right)$, then that's when they should see literally evaluating those expressions give different results

remote foxBOT
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BlockLayer2000