Help explain to me why this happens? (logarithms) | Mathematics | Page 1

shell socket Jul 18, 2025, 2:42 AM

#

shouldn’t it be “ log[3] (6^3x + 1)”which then then becomes “3x log[3] (6) + ..” ? why is the x at the back? please help anybody, tq!!

polar abyssBOT Jul 18, 2025, 2:42 AM

#

icy helm Jul 18, 2025, 2:45 AM

#

from my personal notes

shell socket Jul 18, 2025, 2:46 AM

#

i understand why this happens

#

but shouldnt the x be at the front with the 3

icy helm Jul 18, 2025, 2:47 AM

#

multiplication is commutative

#

the x is not part of the log anymore

#

it's outside the ()

#

so 3 log(something) x = 3x log(something)

#

idk why they put it this way

shell socket Jul 18, 2025, 2:47 AM

#

ooooooh

icy helm Jul 18, 2025, 2:47 AM

#

maybe to show the x at the back

shell socket Jul 18, 2025, 2:48 AM

#

okay thank you so much

icy helm Jul 18, 2025, 2:48 AM

#

nps!

#

!done

polar abyssBOT Jul 18, 2025, 2:48 AM

#

If you are done with this channel, please mark your problem as solved by typing .close

shell socket Jul 18, 2025, 2:48 AM

#

.close

#Help explain to me why this happens? (logarithms)