#Derivatives to evaluate (need someone to go over my answers, Calculus 1)
cobalt veldt
velvet flumeBOT
next zephyr
both seems fine to me
rose grove
1(a) it should be $4e^t$ ,not $4te^t$
pallid graniteBOT
Victimizer
cobalt veldt
when do I ever bring the exponent down? I first thought it was never when it comes to e, but found some examples where they brought the exponent down.
rose grove
1 (b) when u do derivative of $x^4$
U use $nx^(n-1)$ so $4x^(4-1)=4x^3$
pallid graniteBOT
Victimizer
rose grove
when do I ever bring the exponent down? I first thought it was never when it com...
So
e^x will have same derivative that is e^x
cobalt veldt
e^3x will be e^3x?
rose grove
In case of e^(mx )
It will be me^x
rose grove
e^3x will be e^3x?
Nope this follows the 2nd one which i sent
m is the coefficient of x basically
cobalt veldt
oh ok i get it, in number 1 t is what x would be
so it stays the same, its not the coefficient
cobalt veldt
ok that makes sense
rose grove
In case of e^(mx )
It will be me^x
I did a mistake here
cobalt veldt
when do you use ln?
3^x for example? just add ln to both sides
cobalt veldt
I did a mistake here
me^mx?
rose grove
It is supposed to be me^mx
rose grove
1 (b) when u do derivative of $x^4$
U use $nx^(n-1)$ so $4x^(4-1)=4x^3$
Correct this too
Also in 1(b)
Put the "-sinx" in bracs otheriwse it looks like u subtracted sinx
Same mistake in 1(c)
As 1(a)
rose grove
1 (d) u forgot the 1/2 at the very beginning
cobalt veldt
ok thanks a lot
rose grove
1 e same mistake
nx^(n-1)
I think u need to clear up formulas
1f is perfect
Plus
h is perfect
(I)same mistake as me^mx
j perfect
K same mistake
me^mx
2a is perfect
2b has some mistakes
When u go fo e^y ,y is not x here rather it's a function of x
So e^y will hv a derivative of (e^y )(y')
C is all good
cobalt veldt
I think u need to clear up formulas
Power rule and e^x?