Algebra: The Substitution Method | Mathematics | Page 1

pseudo prawn Jul 14, 2025, 11:29 PM

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Having trouble solving this equation for graphing, can someone help explain?

drowsy reefBOT Jul 14, 2025, 11:29 PM

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bitter marsh Jul 14, 2025, 11:35 PM

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Sub given value of x into second equation

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-6(-4y-3) -4y = -82

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And now that it is one variable you can solve for y

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And once you have y you sub that value into any one of the two equations to solve for x

pseudo prawn Jul 14, 2025, 11:38 PM

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ahh so I dont need to put it as 6x?

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or like 6x =

wooden zealot Jul 14, 2025, 11:48 PM

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If u substitute x with y,u dont need to do that but if u substitute y with x then x would stay in the equation

pseudo prawn Jul 14, 2025, 11:50 PM

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so for the first equation would I then format it as
x = -4 x -4 -3

wooden zealot Jul 14, 2025, 11:51 PM

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Nope lemme walk u through this

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For the 1st equation find the value of x with respect to y

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That is keep x alone at one side and y and other constant on the other side

pseudo prawn Jul 14, 2025, 11:54 PM

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so would I keep as it is?

weak hinge Jul 14, 2025, 11:56 PM

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pseudo prawn Having trouble solving this equation for graphing, can someone help explain?

Since we know that,
x = -4y - 3
We can substitute all x’s into the second equation,
-6x - 4y = -82
-6(-4y - 3) - 4y = -82
After expanding,
24y + 18 - 4y = -82
Then, you will solve for y, then substitute y back into any equation (I recommend the first), to solve for x.

pseudo prawn Jul 15, 2025, 12:06 AM

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so then when solving for y we would leave the x as is?

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.close

#Algebra: The Substitution Method