#Graph theory
16 messages · Page 1 of 1 (latest)
I'm an absolute noob, but if you sum up the possibilities for each outgoing edge it should work - i got 25
Denote by A,B,C,D,E,F,G,H,I the number of ways to each corresponding vertex from A. Moving from B backwards you can express each number as a sum of the number of ways to the neighboring vertices. For example you can get to B only from H and I. So, the number of ways from A to B equals the number of ways from A to H plus the number of ways from A to I. Thus B=H+I. And so on, you make equations moving backwards. You get a system of equations, which is easy to solve. Finally, B=16.
why?
F = 1
E = 3
D = 4
A = 1 right?
nope, A=1
Do my 'yes' or ''no'' change anything? It's math. If you understand the solution and see no logical mistake then it is correct. If you see a mistake name it.
by the way, I found a mistake 🙂
In that system D=A+E, because we get into D from A and E, not only A.
So, this is a correct version