#Help with Quantifiers and Equivalences
3 messages · Page 1 of 1 (latest)
It is because of how the parentheses are placed. When a for all x is initialized in a parenthesis, it only exists within that pair of parentheses.
You could instead have
$(\forall y Q(y))$ and it would be the same thing, but there is no ambiguity on the left by replacing y with x because of the parentheses placement