#Find x
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What would you call BDC? (Hint: BAC is the diameter)
90°?

You'll want to use sohcahtoa and law of sines
BDC is a semicircle
Angle BDC = 90 degrees (Angle in a semicircle)
So, you see that Triangle BDC is a right triangle
Next: what is the relationship between Angle ADB and Angle ABD?
Problem solved. Thanks alot for the help 👍
!done
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