Help

[mint tusk]

!show

[ashen wigeon]

Show your work, and if possible, explain where you are stuck.

[mint tusk]

And if possible send a diagram atleast

[cunning yoke]

For a it was simple

But b is impossible

I thought that a was actually a guidance for b, to use PAM=PNM (angles)

To show that is inscribable I tried finding angle OBQ equal to PAM

[raven sorrel]

the right triangles are similar, so they have equal angles.

[cunning yoke]

Yes

How do I use that ?

[raven sorrel]

if two angles with common base are equal then they make an inscribed quadrilateral

[cunning yoke]

wait

Can you explain more

What is the common base

[raven sorrel]

PQ

[cunning yoke]

I still don’t get it

I’m sorry

How do I make a full demonstration

[raven sorrel]

Tbh you've written the problem statement like crap. No Q, what is 2, and in fact the data allow angles from (a) to be not equal. And the figure is the same bad. No markings. I can't even explain which triangles are similar

[cunning yoke]

2 was Q

It was translated

[raven sorrel]

What is H in your figure?

[cunning yoke]

Let me redo everything

1 minute

[raven sorrel]

Red and green triangles are similar

[cunning yoke]

How is AM/BK=OM/OK

I ask too many questions because I want to make sure I understand everything

Not just copy

[raven sorrel]

That's standard in any trapezoid. Just think about it

AM and BK are half diagonals. So just move one diagonal to make a triangle similar to OKM

[cunning yoke]

Ohh

Now it makes sense

But o still can t prove this part

I m trying now

I mean I totally see it, but can t put it on paper

No, I got it

Can t believe I finally understood

🙏 thank you

.close