#Why is the answer not x/log(2)?
vocal canopy
lilac pythonBOT
vocal canopy
isnt this correct?
vocal canopy
wdym
last lantern
last lantern
so u took base as 10?
vocal canopy
yea no shit
last lantern
mb
vocal canopy
where did u even get log(a/b) from i wrote base 2 log 5 not log(5/2)
last lantern
no i thought u used loga-logb
i forgot about change or base 😭
it is x/log2
what did the key say
vocal canopy
idk i still have 2 tries for this question
last lantern
its supposed to be x/log2
eternal wren
maybe they want (1/log2)x idk 💀
last lantern
they want in terms of x only without logs
ohh i c
that they shouldve mentioned man
log2 is constant
naive canyon
Here you go:
Number (2.) on https://examssuccess.appspot.com/MATHEMATICS/ExponentsLogarithms.html
I used the laws of logarithms: Law 6 (Change of base of Log), Law 4 and Law 1
Let me know if you have any questions regarding the solution.
eternal wren
¹⁰log 5 = 1/⁵log 10
I'm confused what you're doing here
left canyon
I'm confused what you're doing here
the answer asks for ²log 5 in terms of x
I reciprocated the original expression cuz 5 is a prime number thus cannot be factorised further
while 10 can
and 10 contains both 2 and 5 as factors which is what we want for ²log 5 with 2 as it's base and 5 as it's argument