#Weird proof
22 messages · Page 1 of 1 (latest)
5 = 4
0 • 5 = 0 • 4
0 = 0
5 = 4 is thus true
you cannot simply multiply by 0
I see
your proof isn't false?
you cant multiply by zero on both sides in arithmetic operations because 0 * <> has no inverse in the set of real numbers
in real number algebraic proofs, zero does not preserve the structure of an equation in the same way other numbers do cuz its not an injective op
but if ur multiplying an operator by 0 that is different.
$0 \cdot \int$ is not formally defined, so you can define it yourself
MARETU
it's lowkey the same thing as this
I’m keeping that thanks
The only part that is false is the last line, where it says because the result is 0=0 which is true, that implies that those two are equal. It doesn’t imply that which makes the proof incorrect.
the only reason itd be incorrect is if multiplying by 0 were not an injective operation
multiplying 0 by an integral symbol is not standard
so aspect can define it however they want
uh yeah that too!
I scrolled too far
wtf does this even MEAN bro
